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.:: AP Students have to secure 87.20% in inter to become eligible for IIT-JEE ::.

The new IIT-JEE pattern to be effective from 2013 makes it mandatory for aspirants to figure in the top 20 percentile of the respective boards. In connection to the new pattern the Council of Boards of School Education (CoBSE) which is the association of various Boards at 10+2 level across the country has released cut-off figures based on the top 20 percentile marks to be secured by students in various 10+2 Board exams this year. Until now, a minimum of 60 per cent in 10+2 was enough to appear for the IIT-JEE. However, with the proposal to allow only students who figure in the top 20-percentile list from each Board to take the test, the cut-off marks for AP students will increase to 87.20 per cent.

If the proposed IIT-JEE test based on the top 20 percentile data comes into force from 2013, AP students will have to secure 87.20 per cent in the Intermediate (10+2) exams, the highest in the country, to become eligible. The next highest state will be Tamil Nadu, whose students will have to get 78.17 per cent. CBSE students across the country, including AP, will need to get 77.80 per cent marks.

Other States with cut off percentages are Kerala (76.5), Punjab (70.8), Karnataka (67.5), Jammu and Kashmir (67), Uttar Pradesh (65), Manipur (64.6), Madhya Pradesh (64) and Rajasthan (63.8). Meghalaya with 49.40 per cent will be the lowest in the country.
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